dpoch1.f
5.26 KB
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double precision function dpoch1 (a, x)
c august 1980 edition. w. fullerton, c3, los alamos scientific lab.
c
c evaluate a generalization of pochhammer-s symbol for special
c situations that require especially accurate values when x is small in
c poch1(a,x) = (poch(a,x)-1)/x
c = (gamma(a+x)/gamma(a) - 1.0)/x .
c this specification is particularly suited for stably computing
c expressions such as
c (gamma(a+x)/gamma(a) - gamma(b+x)/gamma(b))/x
c = poch1(a,x) - poch1(b,x)
c note that poch1(a,0.0) = psi(a)
c
c when abs(x) is so small that substantial cancellation will occur if
c the straightforward formula is used, we use an expansion due
c to fields and discussed by y. l. luke, the special functions and their
c approximations, vol. 1, academic press, 1969, page 34.
c
c the ratio poch(a,x) = gamma(a+x)/gamma(a) is written by luke as
c (a+(x-1)/2)**x * polynomial in (a+(x-1)/2)**(-2) .
c in order to maintain significance in poch1, we write for positive+ a
c (a+(x-1)/2)**x = exp(x*alog(a+(x-1)/2)) = exp(q)
c = 1.0 + q*exprel(q) .
c likewise the polynomial is written
c poly = 1.0 + x*poly1(a,x) .
c thus,
c poch1(a,x) = (poch(a,x) - 1) / x
c = exprel(q)*(q/x + q*poly1(a,x)) + poly1(a,x)
c
double precision a, x, absa, absx, alneps, alnvar, b, bern(20),
1 binv, bp, gbern(21), gbk, pi, poly1, q, rho, sinpxx, sinpx2,
2 sqtbig, term, trig, var, var2, d1mach, dpsi, dexprl, dcot,
3 dpoch, dlog, dsin, dsqrt
external d1mach, dcot, dexprl, dpoch, dpsi
c
c bern(i) is the 2*i bernoulli number divided by factorial(2*i).
data bern ( 1) / +.8333333333 3333333333 3333333333 333 d-1 /
data bern ( 2) / -.1388888888 8888888888 8888888888 888 d-2 /
data bern ( 3) / +.3306878306 8783068783 0687830687 830 d-4 /
data bern ( 4) / -.8267195767 1957671957 6719576719 576 d-6 /
data bern ( 5) / +.2087675698 7868098979 2100903212 014 d-7 /
data bern ( 6) / -.5284190138 6874931848 4768220217 955 d-9 /
data bern ( 7) / +.1338253653 0684678832 8269809751 291 d-10 /
data bern ( 8) / -.3389680296 3225828668 3019539124 944 d-12 /
data bern ( 9) / +.8586062056 2778445641 3590545042 562 d-14 /
data bern ( 10) / -.2174868698 5580618730 4151642386 591 d-15 /
data bern ( 11) / +.5509002828 3602295152 0265260890 225 d-17 /
data bern ( 12) / -.1395446468 5812523340 7076862640 635 d-18 /
data bern ( 13) / +.3534707039 6294674716 9322997780 379 d-20 /
data bern ( 14) / -.8953517427 0375468504 0261131811 274 d-22 /
data bern ( 15) / +.2267952452 3376830603 1095073886 816 d-23 /
data bern ( 16) / -.5744724395 2026452383 4847971943 400 d-24 /
data bern ( 17) / +.1455172475 6148649018 6626486727 132 d-26 /
data bern ( 18) / -.3685994940 6653101781 8178247990 866 d-28 /
data bern ( 19) / +.9336734257 0950446720 3255515278 562 d-30 /
data bern ( 20) / -.2365022415 7006299345 5963519636 983 d-31 /
c
data pi / 3.1415926535 8979323846 2643383279 503 d0 /
data sqtbig, alneps / 2*0.0d0 /
c
if (sqtbig.ne.0.0d0) go to 10
sqtbig = 1.0d0/dsqrt(24.0d0*d1mach(1))
alneps = dlog(d1mach(3))
c
10 if (x.eq.0.0d0) dpoch1 = dpsi(a)
if (x.eq.0.0d0) return
c
absx = dabs(x)
absa = dabs(a)
if (absx.gt.0.1d0*absa) go to 70
if (absx*dlog(dmax1(absa,2.0d0)).gt.0.1d0) go to 70
c
bp = a
if (a.lt.(-0.5d0)) bp = 1.0d0 - a - x
incr = 0
if (bp.lt.10.0d0) incr = 11.0d0 - bp
b = bp + dble(float(incr))
c
var = b + 0.5d0*(x-1.0d0)
alnvar = dlog(var)
q = x*alnvar
c
poly1 = 0.0d0
if (var.ge.sqtbig) go to 40
var2 = (1.0d0/var)**2
c
rho = 0.5d0*(x+1.0d0)
gbern(1) = 1.0d0
gbern(2) = -rho/12.0d0
term = var2
poly1 = gbern(2)*term
c
nterms = -0.5d0*alneps/alnvar + 1.0d0
if (nterms.gt.20) call seteru (
1 49hdpoch1 nterms is too big, maybe d1mach(3) is bad, 49, 1, 2)
if (nterms.lt.2) go to 40
c
do 30 k=2,nterms
gbk = 0.0d0
do 20 j=1,k
ndx = k - j + 1
gbk = gbk + bern(ndx)*gbern(j)
20 continue
gbern(k+1) = -rho*gbk/dble(float(k))
c
term = term * (dble(float(2*k-2))-x)*(dble(float(2*k-1))-x)*var2
poly1 = poly1 + gbern(k+1)*term
30 continue
c
40 poly1 = (x-1.0d0)*poly1
dpoch1 = dexprl(q)*(alnvar+q*poly1) + poly1
c
if (incr.eq.0) go to 60
c
c we have dpoch1(b,x), but bp is small, so we use backwards recursion
c to obtain dpoch1(bp,x).
c
do 50 ii=1,incr
i = incr - ii
binv = 1.0d0/(bp+dble(float(i)))
dpoch1 = (dpoch1 - binv) / (1.0d0 + x*binv)
50 continue
c
60 if (bp.eq.a) return
c
c we have dpoch1(bp,x), but a is lt -0.5. we therefore use a reflection
c formula to obtain dpoch1(a,x).
c
sinpxx = dsin(pi*x)/x
sinpx2 = dsin(0.5d0*pi*x)
trig = sinpxx*dcot(pi*b) - 2.0d0*sinpx2*(sinpx2/x)
c
dpoch1 = trig + (1.0d0 + x*trig)*dpoch1
return
c
70 call entsrc (irold, 1)
dpoch1 = dpoch (a, x)
if (dpoch1.eq.0.0d0) call erroff
call entsrc (irold2, irold)
c
dpoch1 = (dpoch1 - 1.0d0) / x
return
c
end